This voltage regulator input need around 20 Volt to 25 Volt. The voltage regulator with zero ripple voltage regulator with zero fluctuations is the usual parametric stabilizer, but the inverting input of op amp is fed from the potentiometer 10 k of the voltage ripple. These voltages are summed in opposite phase. 10K potentiometer can be adjusted compensation ripple at the output of the stabilizer, to virtually zero.
This circuit will give you a 9V regulated DC voltage at maximum current of about 1A. The circuit uses stepdown tansformer with secondary output voltage of 25V AC and 1A current. The primary voltage depended your home electrical power line installation. If your power line voltage is 110V then you must find transformer 110V primary voltage. The diode can be 4 pieces of 1N4002 (1A rectifier diode) or a 1A bridge diode. (more…)
The actual supply should get -20 V coming from rectifier/filter that is given to the collector of Darlington PNP-type pass transistor, a TIP 105. The base drive for the TIP105 is supplied via resistor R5. The base of the TIP is driven from Vz terminal at pin 9, this is anode of 6.2 V zener diode which links with the emitter of uA 723 output control transistor. The way of providing the positive feedback needed for feedback action is
The actual supply takes +20 Volt Dc through the dioda bridge or filter part. This can be given to pins 11 and 12 on ua723, and also for the collector 2N3055 series-pass transistor. All the output voltage will be sampled through R1 and R2, giving around 7 Volt relating to ground at pin 4. The reference terminal at pin 6 is linked right to pin 5, the noninverting input of the error amplifier. (more…)
A simple 9 Volt 2 amp power supply using a single IC regulator. This is very simple circuit. Everything is done by the regulator. The 78S09 can provide up to 2 amps continuous output while maintaining a low noise and very nicely regulated supply. (more…)
This is a 40V Regulated Power Supply, built using IC LM317 as regulator and TIP42A as electric current amplifier. Component part: Regulated Power Supply R1 = 3R9 1 or 2W R2 = 22R R3 = 6K8 R4 = 220R R5 = 4K7 C1 = 3300µF/50V or 4700µF/50V C2,C5 = 100nF C3 = 10µF/63V C4 = 220µF/50V D1 = Diode bridge 100V 4A D2 = 1N4002 D3 = LED IC1 = LM317T Q1 = TIP42A SW2 = SPST Mains switch
This circuit using KR142EN12 (analog - LM317 ) ic regulator that can handle load currents up to 2 amperes. For higher currents can be used IC LT1083/84/85 that each can handle currents 7/5/3A. 2000uF capacitor C3 is selected from the calculation of the current 1 Ampere. Resistor R9 is used as a current sensor to an ammeter. (more…)